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Title: How to write net ionic equations for basic and acidic solutions? Post by: SakurasFlowers on Oct 28, 2010 How to write net ionic equations for basic and acidic solutions?
Write a balanced net ionic equation for the following reaction in basic solution: 1 ) Zn(s) + NO3- (aq) -> NH3(aq) + Zn(OH)4^(2-) Write a balanced net ionic equation for the following reaction in acidic solution: 2 ) Mg(s) + VO4^(3-)(aq) -> Mg^(2+)(aq) + V^(2+) 3 ) PbO2(s) + CI-(aq) -> PbCI2(s) + O2(g) Title: Re: How to write net ionic equations for basic and acidic solutions? Post by: star on Oct 28, 2010 Zn ------> Zn+2 & 2 electrons lost
(NO3)- & 8 electrons taken ------> (NH4)+ (N+5 in nitrate goes to N-3 in ammonium) four times the Zn reaction to balance the electrons taken & lost: 4Zn ------> 4Zn+2 & 8 e- (NO3)- & 8 e- ------> (NH4)+ combine the two 1/2 reactions: 4 Zn & (NO3)-1 ---> 4 Zn+2 & (NH4)+1 we need to balance the charges on both sides: -1 --> +9,....add 10 (OH-)'s to the right side & you will have 1- --> -1 : 4 Zn & (NO3)-1 ---> 4 Zn+2 & (NH4)+1 & 10 OH- balance the H's using neutral water: 4 Zn & (NO3)-1 & 7 H2O ---> 4 Zn+2 & (NH4)+1 & 10 OH- Also, here is a set-by-set way of doing them: http://tiny.cc/i0i6c (http://tiny.cc/i0i6c) you can get answers or check answers to balanced redox reactions by going to this site! http://www.gregthatcher.org//Chemistry/BalanceChemicalEquations.aspx?StartsWith=O (http://www.gregthatcher.org//Chemistry/BalanceChemicalEquations.aspx?StartsWith=O) Title: Re: How to write net ionic equations for basic and acidic solutions? Post by: bio_man on Oct 28, 2010 Mg (s) + VO43- (aq) --> Mg2+ (aq) + V2+ (aq) (Base)
Mg --> Mg2+ + 2 e- x3 3 e- + 8 H+ + VO43- --> V2+ + 4 H2O x2 3Mg --> 3Mg2+ + 6 e- 6 e- + 16 H+ + 2 VO43- --> 2 V2+ + 8 H2O 3Mg + 16 H+ + 2 VO43- --> 3Mg2+ + 2 V2+ + 8 H2O + 16 OH- on both sides 3Mg + 8 H2O + 2 VO43- --> 3Mg2+ + 2 V2+ + 16 OH |