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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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hcarrera hcarrera
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10 years ago
calculate the molecular weight of a gas if 1.15 grams occupy .215 liter at .813 atm and 30.0 degrees C
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#1
Staff Member
Educator
10 years ago
I think the magic formula here would be to start with PV = nRT.

Here's an example:

You have 7.5 L, 60 atm and 35.5 C (= 308.65K)
and given R = 0.082 [L*atm / mol*K]

n = PV / RT
= (60) [atm] * (7.5) [L] / (0.082) [L*atm / mol*K] * (308.65) [K]
=17.8 mol

Molecular weight is in terms of [g/mol]
So, (35.44) [g] / (17.8) [mol] = 2.0 grams / mole
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