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pineapplelove6 pineapplelove6
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9 years ago
In guinea pigs, black coat B is dominant to white b coat, and short hair S is dominant to long hair s. A black long haired pig is mated with a white short haired one. Several litters were produced and out of the total of thirty eight offspring, ten were black and short, nine were black and long, six were white and short, and thirteen were white and long.

A) what are the most likely genotypes of the parents?

B) what should the phenotypic ratio be theoretically?
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wrote...
9 years ago
This is what I could come up with after working out this problem..

A) The most likely geneotypes of the parents are
Bbss and bbSs.  This is because, this gives rise to 4 different types of gametes where you could then workout the phenotypic ratio based on the punnett square. Well, you may think it could be either BBss and bbSS. If that was the case, only 2 gametes can be formed and there will not be 4 varieties within the phenotypes.  This is same when it comes to BBss and bbSs as only 3 gametes could be formed.  Hence the possible genotype is Bbss and bbSs. This is easily identifiable because the characters long and white present in the parents are written only in homogeneous form.

B) According to the punnett square, theoretically, the phenotypic ratio is as follows:
Black & short: Black&long: White & short: White & long
       2                  5                  5                      4
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