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srmtrc srmtrc
wrote...
Posts: 33
Rep: 1 0
9 years ago
In pea plants, plant height, seed shape, and seed color are governed by three independently assorting loci. The three loci show the following dominance and recessiveness:
Plant height: Tall (T) is dominant to short (t).
Seed shape: Round (R) is dominant to wrinkled (r).
Seed color: Yellow (G) is dominant to green (g).

I know the members of the F2 generation are produced by crossing TtRrGg x TtRrGg

What proportion of the F2 that produce round, green seeds (regardless of the height of the plant) are expected to breed true?
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wrote...
Valued Member
On Hiatus
9 years ago
Why don't you make a Punnett square to find out? true breeds should have genotype RRGG (we don't care about the height).

Since we don't care about the height, we don't need to involve it at our Punnet square:

As you said, the crossing is RrGg x RrGg (we don't need the Tt)
So, the possible gametes are RG Rg rG rg (for both parents)
So, the Punnett should be:

           RG         Rg           rG          rg

RG    RRGG    RRGg      RrGG     RrGg
Rg     RRGg     RRgg      RrGg      Rrgg
rG      RrGG     RrGg       rrGG      rrGg
rg      RrGg       Rrgg       rrGg       rrgg


As you see, only 1/16 plants produce round green seeds AND are breed true.
However, the exercise asks something else:
Quote
What proportion of the F2 that produce round, green seeds (regardless of the height of the plant) are expected to breed true?
We need to find all the plants that produce green and round seeds (true breeds or not): they are:

           RG         Rg           rG          rg

RG    RRGG    RRGg      RrGG     RrGg
Rg     RRGg     RRgg      RrGg      Rrgg
rG      RrGG     RrGg       rrGG      rrGg
rg      RrGg       Rrgg       rrGg       rrgg

They are 9. Out of them, only one breeds true.
So, the answer is: 1/9 plants with round and green seeds are expected to breed true.
srmtrc Author
wrote...
9 years ago
1/9 isn't the answer, unfortunately...
wrote...
Valued Member
On Hiatus
9 years ago
Whops, wait a second, the G allele is the dominant for the color yellow? Who named it as G ?... Anyways...
Let's do this again:

           RG         Rg           rG          rg

RG    RRGG    RRGg      RrGG     RrGg
Rg     RRGg     RRgg      RrGg      Rrgg
rG      RrGG     RrGg       rrGG      rrGg
rg      RrGg       Rrgg       rrGg       rrgg

Firstly, we count the plants with round GREEN seeds. That is, plants with genotypes RRgg or Rrgg:

           RG         Rg           rG          rg

RG    RRGG    RRGg      RrGG     RrGg
Rg     RRGg    RRgg      RrGg      Rrgg
rG      RrGG     RrGg       rrGG      rrGg
rg      RrGg      Rrgg       rrGg       rrgg

They are 3. Out of them, only one is breeding true: The RRgg. So, the answer is 1/3.

Well, I was wrong but you shouldn't just copy paste the answer without understanding how it is done. You should've been able to find the mistake on your own.
srmtrc Author
wrote...
9 years ago
That's correct, thank you! I'd been struggling with that problem for so long that I think I forgot how to look at it, but your description was very helpful. Thanks again.
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