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Home Q & A Board Science-Related Homework Help Mathematics
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lexieanderson01 lexieanderson01
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9 years ago
Not sure how to do this one. (y^2-11y+33)/(y-6)
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wrote...
#1
Valued Member
On Hiatus
9 years ago
It is clear that this exercise need factorization. To factorize an expression x2 + ax + b, you need to find two numbers (let's name them c and d) so that c+d=a and c*d=b

But, in your case, I think something is wrong. Maybe you meant o write (y^2-11y+30)/(y-6) ?
wrote...
#2
9 years ago Edited: 9 years ago, Xilch
isolate and expand the equation:

(y² - 11y + 33)
y - 6

=
__33__    -  __11y__    +   __y²__
  y - 6           y - 6              y - 6

that should be the answer; since you cant further simplify it; unless you're looking for plot diagrams then im not sure how to input it here.
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#3
Educator
9 years ago
Quote from: Alexx (9 years ago)
(y^2-11y+30)/(y-6)

Yes, that's factor-able, whereas what was originally written isn't.
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#4
9 years ago
you just wrote down the wrong thing
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#5
9 years ago
y^2-11y+33=(y-6)*(y-5)+3
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#6
Valued Member
On Hiatus
9 years ago
Hm, that's an interesting approach. It could be correct. However, I don't think that would help while solving an actual exercise.
We will end up with y-5 +3/(y-6) . In my opinion, that is quite as bad as having (y^2-11y+33)/(y-6)
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#7
Valued Member
On Hiatus
9 years ago
I'll try but don't know if this is right.. hope this helps
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