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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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krustythe krustythe
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9 years ago Edited: 9 years ago, krustythe
You need to make a 500 mM glycine buffer (pKa= 9.78) at pH 9.9.  How will you prepare 1 L of this buffer using glycine (75.07 g/mol) and NaOH (1.0 M)?
Post Merge: 9 years ago

So I know I need to use Henderson hasselbach equation:

pH = pKa  + log ([A^-])/([HA])
   = 9.78 + log ([A^-])/([HA])
0.22 = log ([A^-])/([HA])
〖10〗^.22 = 〖10〗^(log ([A^-])/({HA]))
1.66 = ([A^-])/([HA])

...I am confused from here
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AlexxAlexx
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9 years ago
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krustythe Author
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9 years ago
Alexx,

Thanks a lot for the explanation. The question makes so much more sense now. I really really really really want to thank you for taking the time to explain it so well. I have been siting here for hours trying to figure it out.THANK YOU!!!!!!!! Slight Smile Slight Smile Slight Smile Slight Smile Slight Smile
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