Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
krustythe krustythe
wrote...
Go to Answer
Posts: 16
Rep: 0 0
9 years ago Edited: 9 years ago, krustythe
You need to make a 500 mM glycine buffer (pKa= 9.78) at pH 9.9.  How will you prepare 1 L of this buffer using glycine (75.07 g/mol) and NaOH (1.0 M)?
Post Merge: 9 years ago

So I know I need to use Henderson hasselbach equation:

pH = pKa  + log ([A^-])/([HA])
   = 9.78 + log ([A^-])/([HA])
0.22 = log ([A^-])/([HA])
〖10〗^.22 = 〖10〗^(log ([A^-])/({HA]))
1.66 = ([A^-])/([HA])

...I am confused from here
Read 466 times
2 Replies
Replies
Answer accepted by topic starter
AlexxAlexx
wrote...
#1
Valued Member
On Hiatus
Top Poster
Posts: 998
Rep: 254 3
9 years ago
Sign in or Sign up in seconds to unlock everything for free
This verified answer contains over 400 words.
1

Related Topics

krustythe Author
wrote...
#2
9 years ago
Alexx,

Thanks a lot for the explanation. The question makes so much more sense now. I really really really really want to thank you for taking the time to explain it so well. I have been siting here for hours trying to figure it out.THANK YOU!!!!!!!! Slight Smile Slight Smile Slight Smile Slight Smile Slight Smile
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1315 People Browsing
 132 Signed Up Today
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 839
  
 156
  
 328
Your Opinion
What's your favorite math subject?
Votes: 293
Previous poll results: Do you believe in global warming?