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fodog414 fodog414
wrote...
Posts: 279
9 years ago
Calculate ∆H for the reaction

C6H4(OH)2(aq) + H2O2(aq) → C6H4O2(aq) + 2 H2O(l)

given the following data:

Equation                                                           ∆H (kJ)
C6H4(OH)2(aq) → C6H4O2(aq) + H2(g)   177.4

H2(g) + O2(g) → H2O2(aq)                           -191.2

H2(g) + ½ O2(g) → H2O(g)                           -241.8

H2O(g) → H2O(l)                                           -48.8

∆H =   kJ

I understand that you have to figure out the products and the reactants and flip the sign accordingly

I also get that you have to get rid of the fractions so Delta H would also be multiplied

But for some reason I keep missing up

With only one attempt left Frowning Face

Could anyone guide me?
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6 Replies
Replies
wrote...
Valued Member
On Hiatus
9 years ago
Hi,
Can you post the answers you tried so far? It doesn't seem terribly hard, you might did some miscalc or other mistake.

I'll also work with the exercise now and repost with my solution.
Answer accepted by topic starter
AlexxAlexx
wrote...
Valued Member
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Posts: 998
9 years ago
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fodog414 Author
wrote...
9 years ago Edited: 9 years ago, fodog414
The computer randomizes to a different question when you get it wrong but I got 93.6

because wouldn't C6H4(OH)2(aq) → C6H4O2(aq) cancel each other out?

Leaving H202>> and 2H20 which means flip -191.2 to a positive form and keep H20 the same but times by 2?

so 191.2+2(-48.8)=93.6
Post Merge: 9 years ago

From what It looks like i think you are right i'll have to go over it again tomorrow to double check

But overall thank you!! Very clear and concise Slight Smile Astonished Face
wrote...
Valued Member
On Hiatus
9 years ago
Quote
because wouldn't C6H4(OH)2(aq) → C6H4O2(aq) cancel each other out?
Why should they cancel each other? They are two different molecules.

Quote
Leaving H202>> and 2H20 which means flip -191.2 to a positive form and keep H20 the same but times by 2?
There is no such reaction. The reaction you are looking is: H2O2(aq)  →  H2(g) + O2(g) which is different.

I think you are a bit confused?
fodog414 Author
wrote...
9 years ago
What i was trying to get at was sense C6H4(OH)2(aq) → C6H4O2(aq)+H2 is the reaction shouldn't they be inversely proportioned to each other? Because wouldn't that mean that sense it takes 177. delta H kj to make C6H4(OH)2(aq) → C6H4O2(aq)+H2

It should also take -177.4 to produce  C6H4O2(aq)+H2 → C6H4(OH)2(aq) ??

On the second part I understand that there is no such reaction but I was just focusing on the heat energy, because the other reactants and products are still there but H2=0 and from the above reasoning -177.4 +177.4 cancel each other out.

leaving H202 and 2H2O

Though from my earlier reply i'm pretty sure you are correct, I'll know for sure by Sunday Nerd Face
fodog414 Author
wrote...
9 years ago
Thank you Alexx, I have a much stronger understanding now Slight Smile
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