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fodog414 fodog414
wrote...
Posts: 279
9 years ago
The electron configuration of a particular diatomic species is
 (sigma2s)^2 (anti-bonding sigma*2s)^2 (sigma 2p)^2 (pi2p)^4 (anti-bonding pi*2p)^1
 What is the bond
order for this species?
A) 4
B) 3.5
C) 3
D) 2.5
E) 2


could someone explain the pi2p^4 orbit? Is that supposed to be pi2p^2?

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7 Replies
Replies
wrote...
Educator
9 years ago
Hey fodog414, see if the answer can be found in one of the two attachments. Answers are at the end of the document in case you're wondering!
 Attached file(s) 
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fodog414 Author
wrote...
9 years ago
No luck :/ but thank you for looking!
Answer accepted by topic starter
skip5284skip5284
wrote...
Posts: 159
9 years ago
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fodog414 Author
wrote...
9 years ago
I think i have a small handle on MO diagrams but i'm just getting confused on the pi2p^4 does that ^4 signify 4 electrons in the orbit?
wrote...
Educator
9 years ago
Hey fodog414, could you provide us an update on the solution to this?
fodog414 Author
wrote...
9 years ago
Ya of course I thought I replied to all the questions

Its actually quite easy

there are 8 bonding electrons and there are 3 antibonding electrons

so its 8-3/2

which is 2.5
D
wrote...
Educator
9 years ago
Oh nice, so skip5284 was right! Will mark as solved.
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