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peaches+cream peaches+cream
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9 years ago
Question one:
Feather colour in pararkeets is controlled by two genes. For one pigment gene, the B allel produces blue colour and the b allele does not produce any colour. For the other pigment gene, the Y allel produces yellow colour and the y allele does not produce any colour. Any genotype containing at least one B allele and one Y allele will produce a green parakeet.

Which of the following parental genotypes could produce offspring with the four colour patterns?

A. bbYY x bbyy
B. BbYY x Bbyy
C. BBYy x BbYy
D. Bbyy x bbYy

HINT: Use a punnett square to demonstrate your answer is correct. Do you need punnett squares of size 4 rows X 4 columns?

(I'm thinking that the answer is B, but I don't know if I did the work right).


Question two:
(Almost like the last question) But now it asks:
What is the probability of obtaining a blue parakeet when two green heterozygous parakeets are crossed?

A. 0
B. 9/16
C. 3/16
D. 1/4


If anyone could help me understand it would be much appriciated!!!  Slight Smile
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wrote...
Educator
9 years ago
Hope the attachment helps...
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peaches+cream Author
wrote...
9 years ago
Thank you!! But im also hoping for an explination too so when I go into the exam and come across a question like this one ill know how to do it Face with Stuck-out Tongue
wrote...
Educator
9 years ago
Hey peaches+cream, it's easy to do, but just very time consuming, because you will have to create four dihybrid crosses, like:

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wrote...
3 years ago
thank you
wrote...
3 years ago
Thank you.
wrote...
3 years ago
thank you!
wrote...
3 years ago
THANk you
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3 years ago
thank u
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3 years ago
than you
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3 years ago
thank you
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3 years ago
thank you
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3 years ago
thank you
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3 years ago
thank you
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