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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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Jellyf11bio Jellyf11bio
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9 years ago
5´—TAC ATG ATC ATT TCA CGG AAT TTC TAG CAT GTA—3´

3´—ATG TAC TAG TAA AGT GCC TTA AAG ATC GTA CAT—5´

the question is saying it encodes 5 amino acids, and considering the start codons and stop codons I still am not able to figure out how it encodes 5 amino acids and its frustrating  Undecided. the top strand is the strand that's to be transcribed, right?
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#1
Educator
9 years ago
Quote from: Jellyf11bio (9 years ago)
5´—TAC ATG ATC ATT TCA CGG AAT TTC TAG CAT GTA—3´

If we use this as the template, we get:

UAC AUG AUC AUU UCA CGG AAU UUC UAG CAU GUA

AUC AUU UCA CGG AAU UUC Rightwards Arrow Results in five amino acids.
wrote...
#2
9 years ago
but the start codon also results in an amino acid?
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#3
9 years ago
if an inversion occurs between the second and the third triplets from the left and right ends of the transcribed strand, how low will the polypeptide be then? still 5 amino acids or no?
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#4
Educator
9 years ago
Quote from: jelly (9 years ago)
but the start codon also results in an amino acid?

Methionine, right? Could you post the question as stated word for word from your assignment, if possible?
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