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Home Q & A Board Science-Related Homework Help Mathematics
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adhungan adhungan
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Posts: 61
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9 years ago
Suppose
f(x) = Px^2+Qx+R
is a general quadratic polynomial with P is not equal to 0 and let [a,b] be any interval. According to the Mean Value Theorem there is at least one number c such that
f(b)-f(a) = f'(c)(b-a).
Actually, in this particular case the number c is unique and it's independent of the coefficients of f. In fact,
c=
Your answer will be in terms of a and b.
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#1
Valued Member
On Hiatus
9 years ago Edited: 9 years ago, alyssa_19
  
 px^2 + qx + r = 0. Use the Quadratic Equation which is x = [- b +/- sq rt(b^2 - 4ac)] / 2a. For your equation, a = p, b = q and c = r. Put these values in the QE and solve for x.

 x = [- q +/- sq rt(q^2 - 4pr)] / 2p.

Or you can also write in this form  Slight Smile

 x = [- q + sq rt(q^2 - 4pr)] / 2p. One Answer.

 x = [- q - sq rt(q^2 - 4pr)] / 2p. Other Answer.
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