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MikeMello MikeMello
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9 years ago


The following cross is performed involving 5 loci: AaBbccDdEE X AaBbCcddEe

What is the probability of an offspring that is AABBCCDDEE?

What is the probability of an offspring that is AaBbCcDdEe?

What is the probability of an offspring that is aabbccddEE?

What is the probability of an offspring that is AaBBccDdEe?

What assumption do you have to make for these probabilities to be true?
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9 years ago
Is there anyway to calculate a punnett square with 5 or more traits quickly?

Say, AaBbCCDdEe x aaBbccDdee

Punnet squares get unwieldy for more than two genes. You won't get a question which tells you to list all possible genotypes and their frequencies in which you have to use a Punnet square. You will be expected to find the frequency of a particular genotype in the progeny. For instance, in the cross AaBbCCDdEe x aaBbccDdee, find the frequency (or probability) of the genotype aaBbCcddEe. Just treat them as a bunch on singlegene Punnet squares:

The probability of the offspring having the genotype aa: P(aa) = 1/2*1 = 1/2

The probability of the offspring having the genotype Bb: P(Bb) = 1/2

The probability of the offspring having the genotype Cc: P(Cc) = 1*1 = 1

The probability of the offspring having the genotype dd: P(dd) = 1/2*1/2 = 1/4

The probability of the offspring having the genotype Ee: P(Ee) = 1/2*1 = 1/2

So the probability of the aaBbCcddEe genotype is P(aaBbCcddEe) = 1/2*1/2*1*1/4*1/2 = 1/32
Source  http://biology-forums.com/index.php?topic=155764.0;highlight=punnett
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