Vinegar, which is just a dilute acetic acid solution, is very common and versati

Assume that we have 100g solution, we have 5g of acetic acid.
#mole of acetic acid (C2H4O2) = 5/60 = 1/12 mol
Volume of solution = m/d = 100/1.01 = 99ml
Concentration of acetic acid = n/v = (1/12) / (99x10^-3) =0.84175M

a. V1M1 = V2M2 so, M2 = (V1M1)/V2
with  V1 is the volume of old vinegar
   V2 is the volume of new vinergar
   M1 is the concentration of old vinegar
   M2 is the new concentration of new vinegar
and V2 = 4 V1
so, M2 = (1/4)M1 = 0.25 x 0.84175M = 0.2104M

b. #mole of new vinegar = MxV= 0.2104M x 0.4732L =0.099956mol
0.099956mol vinegar x(6.022x10^23 molecules vinegar/ 1 mol vinegar) = 6.00x10^22 molecules vinegar

c. in one molucule of vinegar, we have 2 atoms of C
therefore, 6.00x10^22 molecules vinegar x (2 atoms C/ 1 molecule vinegar) =1.2x10^23 atoms C

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