× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
o
5
4
m
4
b
4
x
4
a
4
l
4
t
4
S
4
m
3
s
3
New Topic  
Sektor404 Sektor404
wrote...
Posts: 125
Rep: 0 0
9 years ago
Hi  Slight Smile

For our chemistry class we obtained the following results for concentration calculations used to determine the Nernst Distribution Law for our experiment:

PART 1

0.00096
0.00077
0.00058
0.00037
0.00017

PART 2

0.00016
0.00012
0.00010
0.000066
0.000029

The concentrations were then used to determine 'N' or the Distribution Coefficient for each 'set' of results (Value from Part 1 / Value from Part 2) as represented below:

 0.00096 / 0.00016 = 6.00
 0.00077 / 0.00012 = 6.42
 0.00058 / 0.00010 = 5.80
 0.00037 / 0.000066 = 5.60
 0.00017 / 0.000029 = 5.86

The total average of these N values = 5.93 which is my final average for the Distribution Coefficient (N) from both parts of the experiment. The question also asks to provide the error value along with this answer, how do I do this?? Is there an equation because I am really stuck on something I assume is really simple  Frowning Face

If anybody could help me that would be amazing, thanks kindly.

Read 1166 times

Related Topics

New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  975 People Browsing
Related Images
  
 858
  
 296
  
 122
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 308