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zlr zlr
wrote...
Posts: 7
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8 years ago
A group of biology students are assisting a researcher from the University of Toronto on a project. They are trying to determine the growth rate of frogs in a marsh near Owen Sound.  There are 200 frogs in the first year.  By the time the students are in grade 12, 40 frogs were born, 90 died and 5 frogs immigrated. Determine the growth rate.

This is my attempt. I used this formula:

[(births + immigration)] – (death + emigration)]/initial population size x 100%

= [(40+5) - (90+0)]/200 x 100%
= -45/200 x 100%
= -0.225 x 100%
= -22.5%

Probably a dumb question but can you have a negative rate of change? I don't feel like it's right... Confounded Face
Should I have used the formula λ  = N (t + 1)/N (t) instead?

Thank you so much for the help!
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wrote...
Educator
8 years ago
Probably a dumb question but can you have a negative rate of change?

Yes, you can.

Should I have used the formula λ  = N (t + 1)/N (t) instead?

What do these variables stand for?
zlr Author
wrote...
8 years ago
Probably a dumb question but can you have a negative rate of change?

Yes, you can.

Should I have used the formula λ  = N (t + 1)/N (t) instead?

What do these variables stand for?

lambda = rate of geometric growth
N = initial population
t = time
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