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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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buffyl13 buffyl13
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12 years ago
From this reaction 0.805 grams of NH3 was produced by combining 2.55 grams of N2 with excess H2. What is the percent yield of this reaction? (Enter as a number between 0 and 100, with no units.)
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#1
12 years ago
Let UNITs guide you; always USE THEM in your calculation to prevent errors

eqn: N2 + 3H2 ----> 2NH3

theoretical g of NH3 = 2 moles NH3/mole N2 * (2.55 g N2/MW N2 in g/mole) * MW NH3 in g/mole = ??

% yield = 100% * 0.805 g / theoretical g of NH3 = ??

Plug and SOLVE

Basic mathematics is a prerequisite to chemistry ? I just try to help you with the methodology of solving the problem - SciMann
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