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ryanlovesbigban ryanlovesbigban
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8 years ago
Which of the changes listed below will shift the equilibrium to the right for the following reversible reaction?
C(s) + H2O(g)  CO(g) + H2(g) + heat
Question 1 options:
   
increase [H2O]
   
decrease [H2]
   
increase volume
   
decrease temperature
   
all of the above
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wrote...
Educator
8 years ago
The answer is: d- increase (CO)

CO(g) + H2O(g) <=> CO2(g) + H2(g) + heat

Increasing CO shifts equilibrium to right according to Le Chatelier's principle

Increasing temperature (= adding heat) shifts equilibrium to left according to Le Chatelier's principle as reaction is exothermic

Increasing volume has no effect on equilibrium as there is no changes in moles of gas

Increasing CO2 shifts equilibrium to left according to Le Chatelier's principle

Adding catalyst has no effect on equilibrium
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