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victoria1 victoria1
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Posts: 161
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7 years ago
Use Leonardo's table of chords to solve the following: Suppose a given chord in a circle of diameter 10 is 8 rods, 3 feet, 16 2/7 unciae. Find the length of the arc cut off by the chord.
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Replies
wrote...
7 years ago
FOLLOW THIS Arc length= rx, where x = angle in radians. 60 = 12x, x = 5 A radius will bisect the chord at a 90 degree angle and also bisect the angle at the centre, so sin (x/2) = 1/2 chord / radius 12 sin 2.5 = 1/2 chord, chord = 24 sin(2.5) = 14.36 You can do the second one by realizing that the two large triangles have a side in common. You then find common size angles by knowing that all the angles in any triangle add up to 180. Just work with the combinations and you can find two or more equal angles in the two large triangles. Two angles and a side equal means the triangles are equal, so you prove it that way.
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sem1991sem1991
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7 years ago
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3 years ago
I had this same question! I am stuck because I can't figure out how to read the table and it doesn't explain in the book...
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Valued Member
Educator
3 years ago
I had this same question! I am stuck because I can't figure out how to read the table and it doesn't explain in the book...

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