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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Steptim Steptim
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Posts: 42
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10 years ago
A 5.00-mL sample of a sulfuric acid solution of unknown concentration is titrated with a 0.1401 M Sodium Hydroxide solution. A volume of 5.99 mL of the base was required to reach the endpoint. What is the concentration of the unknown acid solution? Write the neutralization reaction, balance it, name the products THEN Solve the problem above.
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wrote...
#1
10 years ago
5 * M = 0.1401 * 5.99
M = 0.168 M
wrote...
#2
10 years ago
at equivalance point,


m1v1= m2v2,

5* 0.1401 = m2 *5.99,

m2 =0.1169449081803005 M,


H2SO4 + 2NaOH =Na2SO4+2H2O neutralisation reaction
wrote...
#3
10 years ago
m1v1= m2v2, 5* 0.1401 = m2 *5.99, m2 =0.1169449081803005 M, H2SO4 + 2NaOH =Na2SO4+2H2O neutralisation reaction
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