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9 years ago
Thank you! Life saver~
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9 years ago
Thanks for the help.
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9 years ago
this is the answer
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9 years ago
nice
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9 years ago
Thank you
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9 years ago
thank you
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9 years ago
Part C - Predicting genotypes and phenotypic frequencies of progeny
For the cross in Part B, predict the frequencies of each of the phenotypes in the F1 progeny, and determine the genotype(s) present in each phenotypic class.
wrote...
9 years ago
Answering this question requires two logical steps:
First, eliminate those genotypes that are inconsistent with the phenotypes of the parents.
Then examine the remaining possibilities: Which are consistent with the phenotypes of the progeny?
Because the cross produces green progeny (and both parents are yellow), both parents must be Gg: If either parent were GG, only yellow progeny would result.

The cross also produces wrinkled progeny, so the [round, yellow] parent must be heterozygous (Rr): If it were RR, all of the progeny would be Rr and have a round phenotype.
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9 years ago
Thanks so much!
wrote...
9 years ago
this is the answer
Thank you! You are a life saver!!
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9 years ago
Thanks!
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9 years ago
Thank you
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9 years ago
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9 years ago
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