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Orifice plate Trubine Flowmeter

Ryerson University
Uploaded: A year ago
Contributor: bolbol
Category: Chemical Engineering
Type: Other
Rating: (1)
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Filename:   Orifice plate _ Trubine Flowmeter.docx (31.31 kB)
Page Count: 4
Credit Cost: 1
Views: 76
Last Download: N/A
Transcript
Experimental Data and Result Sheet Experiment 5 Orifice plate & Turbine Flowmeter Flowrate in 1/4" pipe (gpm) Co 0.45 0.24 0.50 0.23 0.55 0.23 0.60 0.24 0.65 0.24 0.70 0.23 Flowrate in 1/2" pipe (gpm) Co 0.45 0.32 0.50 0.29 0.55 0.27 0.60 0.28 0.65 0.27 0.70 0.27 At Q =0.60gpm in the 1/2” pipe, Co =0.28 Diameter of the orifice in the 1/2” pipe in step 5 = 0.69 inch Note: Physical properties of water can be used in calculations Calculations: 1 m = 39.3701 inch D1= pipe diameter, 0.302 inch = 0.00767 m D2= orifice diameter, 0.22 inch = 0.00559 m water=1000 kg/m3 8096252540000Q = 0.45 gal 1m3 209550254000min 15852 s = 28.4 x 10-6m3/s A pipe = (D2/4) = [* (0.00767)2] /4 = 0.0000462 m2= 4.62 x10 -5m2 A orifice = (D2/4) = [* (0.00559)2] /4 = 2.45 x10 -5m2 Kinematic Viscosity of water at room temperature = 8.9143x 10-7 m2/s Re= 4Q / D = 4 (28.4 x 10-6)/ * (0.00767)*(8.9143x 10-7) = 5288.7 Table1. Calculation of the Reynolds number for a ¼ pipe Flow rate Q (m3/s) Reynolds number of ¼ pipe 28.4 x 10-6 5288.7 31 x 10-6 5904.8 34 x10-6 6476.2 38 x 10-6 7238.1 41 x 10-6 7809.5 44 x 10-6 8381.0 Sample calculation for determine the coefficient Co of the 1/2 pipe: 38 x 10-6= Co*2.45 x10 -5m2/ [1-(2.45 x10 -5/4.62 x10 -5)2]1/2[(2 *1*15151.2pa)/1000]1/2 Co = 0.28 Determine the size of the orifice for ½ pipes using the equation in step 1, given that D1 = 0.546 in. D1= 0.013868 m 38 x 10-6=0.24 * A2 / [1-(A2/ 1.5x10-4m) 2]1/2[(2 *1*10997.1pa)/1000]1/2 A2= 0.000242051 2.4 x 10 -4m D2= (4A2/) = (4* 2.4 x 10 -4 m/) = 0.01756 m 0.69 inch Discussion: The purpose of this lab was to determine the coefficient of the unknown orifice for ½ pipes by calculating the pressure drops and the volumetric flow rate for the fluid in the pipe. The orifice constant coefficient was calculated experimentally and found to be around 0.28. It was calculated theoretically as well and found to be 0.28 which indicated that the procedure was done accurately and skillfully and the measurements of the pressure drop and the flow rate was recorded precisely so there was no major error in this experiment that can be discussed. Figure1: The Orifice Coefficient Vs. Reynolds number Re

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