Iron in the form FeCl2 can be determined by titration with potassium dichromate:
6 FeCl2(aq) + K2Cr2O7(aq) + 14 HCl(aq) → 6 FeCl3(aq) + 2 CrCl3(aq) + 2 KCl(aq) + 7 H2O(l)
An iron sample of mass 0.800 g required 18.80 mL of 0.0120 M K2Cr2O7(aq) to reach the end point. How many moles of FeCl2 were in the sample?
▸ 1.43 × 10-2 mol
▸ 1.35 × 10-3 mol
▸ 3.75 × 10-5 mol
▸ 2.26 × 10-4 mol
▸ 1.13 × 10-4 mol