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Question

A solution of artificial tears is 0.090% (m/m) sodium chloride. How many grams of sodium chloride are contained in 1.00 g of this solution?
A) 9.0 × 10-4 g
B) 9.0 × 104 g
C) 9.0 g
D) 0.090 g
E) 1.0 g

Answer

15 Seconds

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