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Title: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 13, 2014 msg me
Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B on Feb 13, 2014 Content hidden
Title: Re: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 13, 2014 dw im done #8
and 7 Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B on Feb 13, 2014 #5:
380, 120, 120, 380 6. If the percent G + C content of a DNA molecule is 34%, then what are the percentages of the four individual bases (A,T,G and C) (1 mark)? %A=33 %T=33 %G=17 %C=17 #4: 1,2,4,5 Title: Re: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 13, 2014 and 4
Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B on Feb 13, 2014 #3:
PQMON 3,1,2,4 (they all require P, 3 requires Q, 1 requires M, 2 requires O, and 4 requires N) Title: Re: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 13, 2014 are you sure about 3 i got nomqp
Title: Re: willing to pay $$ for help with a genetics problem set Post by: padre on Feb 14, 2014 Title: Re: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 14, 2014 lol definitely
Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B on Feb 14, 2014 1a.
Cb Ge---------Cb---------St 7.1 7.1 Interference = 1 - Observed DR/Expected DR 1 - 6/5.041 = -0.19024 Not sure. Go with what you think It's one or the other. Just can't think of if it's forward or backward. For #2a: +++ is missing because those are the females who are unaffected 2b: bac That's all I got. Good luck. Just checked it. It's NOMQP Title: Re: willing to pay $$ for help with a genetics problem set Post by: toodaloo on Feb 14, 2014 can you check #1 again based on this attachement
it's a very similar question except some +'s and - are in different places oh and the numbers are different clearly Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B htt on Feb 14, 2014 nvm figured it out :D
Title: Re: willing to pay $$ for help with a genetics problem set Post by: Doctor-2-B on Feb 14, 2014 a.
Cb b. Ge-Cb (46+43+6)/1000 = 0.095 * 100 = 9.5 mu Cb-St (22+19+6)/1000 = 0.047 * 100 = 4.7 mu Ge----------------------Cb-----------St 9.5 mu 4.7 mu c. Observed double recombinants: 6 Expected double recombinants: (0.095)(0.047) = 0.004465*1000 = 4.465 Interference = 1 - 6/4.465 = -0.34378 |