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Title: Consider a circular roller coaster loop of radius 12.2 m. You already know that Post by: tjaen9229 on Oct 22, 2014 Consider a circular roller coaster loop of radius 12.2 m. You already know that if the car starts from a height of 2.5 r at rest, the normal force acting on the car at the top will vanish.
Now assume the car starts from a level track, a height of 12.2 m above the ground. The track first guides the car to ground level and then into the loop. At which initial speed must the car move on the elevated track (height 12.2 m) such that it still has the required speed at the top of the loop for the normal force to vanish? Title: Re: Consider a circular roller coaster loop of radius 12.2 m. You already know that Post by: wizarddim on Oct 23, 2014 Similar Question 1. Consider a circular roller coaster loop of radius 15.1 m. You already know that if the car starts from a height of 2.5 r at rest, the normal force acting on the car at the top will vanish. Now assume the car starts from a level track, a height of 15.1 m above the ground. The track first guides the car to ground level and then into the loop. At which initial speed must the car move on the elevated track (height 15.1 m) such that it still has the required speed at the top of the loop for the normal force to vanish? Answer Vb² = 2g(2.5r) = 5gr 5gr = Vi² + 2gr → Vi² = 3gr → Vi = SQRT[3gr] = 21.07 m/s Title: Re: Consider a circular roller coaster loop of radius 12.2 m. You already know that Post by: bio_man on Oct 23, 2014 Another...
Similar Question Consider a circular roller coaster loop of radius 15.9 m. You already know that if the car starts from a height of 2.5 r at rest, the normal force acting on the car at the top will vanish. Now assume the car starts from a level track, a height of 15.9 m above the ground. The track first guides the car to ground level and then into the loop. At which initial speed must the car move on the elevated track (height 15.9 m) such that it still has the required speed at the top of the loop for the normal force to vanish? Attached is the answer. :) Title: Re: Consider a circular roller coaster loop of radius 12.2 m. You already know that Post by: tygooie on Oct 23, 2014 Vb² = 2g(2.5r) = 5gr
5gr = Vi² + 2gr → Vi² = 3gr → Vi = SQRT[3gr] = 21.07 m/s |