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Title: Find the inflection points of: x^2 - 20x + 36 Post by: bio_man on Nov 30, 2019 Let's begin by finding the first derivative:
\(x^2-20x+36\) First derivative: \(2x-20\) Second derivative: \(2\) From here, the second derivative doesn't have any critical points because all the x's are gone. In other words, you can't set the second derivative equal to zero. This means that there isn't an inflection point for a quadratic or any second degree equation. Title: Re: Find the inflection points of: x^2 - 20x + 36 Post by: zxcvbnm123 on Dec 1, 2019 Thanks for the explanation!
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