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Title: King Kong falls from the top of the Empire State Building, through the air (air Post by: ppk on Apr 10, 2012 King Kong falls from the top of the Empire State Building, through the air (air friction is present), to the ground below. How does his kinetic energy (K) just before striking the ground compare to his potential energy (U) at the top of the building?
A) K is equal to U. B) K is less than U. C) K is greater than U. D) It is impossible to tell. Title: Re: King Kong falls from the top of the Empire State Building, through the air (air Post by: CEPA on Apr 10, 2012 B) K is less than U.
Title: Re: King Kong falls from the top of the Empire State Building, through the air (air Post by: ppk on Apr 10, 2012 Awesome :D
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