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Title: A 50.00-mL solution of 0.0423 M acetic acid (Ka = 1.8 105) is titrated with a 0.0249 M solution of ... Post by: sfern on Mar 21, 2021 A 50.00-mL solution of 0.0423 M acetic acid (Ka = 1.8 × 10–5) is titrated with a 0.0249 M solution of sodium hydroxide as the titrant. What is the pH of at the equivalence point? (Kw = 1.00 × 10–14) ▸ 8.47 ▸ 5.53 ▸ 4.74 ▸ 10.73 ▸ 9.26 Title: A 50.00-mL solution of 0.0423 M acetic acid (Ka = 1.8 105) is titrated with a 0.0249 M solution of ... Post by: Augustdor on Mar 21, 2021 Content hidden
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