Title: Maximum Mass Of s8 Post by: s.h_math on Jan 31, 2024 I am so clueless on how I can get this? I've tried ever calculation in the other hw and on my last try thankfully I still have the same set hw to do similar qs
This is what I was doing as per calculations: 83.0 x 1 /64.1 x 3/8 x 257 83 x 1/34.1 x 3/16 x 257 What is the maximum mass of S8 that can be produced by combining 83.0 g of each reactant? 8S02 + 16H2S —4 3S8 + 16H20 Step 1: Convert 83.0 g S02 to moles and determine the number of moles of S8 that can form from the available amount of S02 83.0 g S02 moles of S8 produced from S02 mol S02 mol S8 Step 2: Convert 83.0 g 1--12 S to moles and determine the number of moles of S8 that can form from the available amount of 1-12 S. 83.0 gH2S moles of S8 produced from 1--12S: mol H2S mol S8 Step 3: Identify the limiting reactant. 2 Calculate the mass of S8 produced from the number of moles of S8 produced from the limiting reactant. Title: Re: Maximum Mass Of s8 Post by: bio_man on Feb 1, 2024 Content hidden
Title: Re: Maximum Mass Of s8 Post by: s.h_math on Feb 1, 2024 THANK YOU BIOMAN
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