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Title: Calculate the amount of water (M.W. = 18.02 g/mol) at its boiling point that wou Post by: tree12 on Feb 20, 2015 Calculate the amount of water (M.W. = 18.02 g/mol) at its boiling point that would be vaporized by 180 Calories (note the capital C). The heat of fusion for water at its boiling point is 40.7 kJ/mol, and 1 calorie = 4.184 J.
Title: Re: Calculate the amount of water (M.W. = 18.02 g/mol) at its boiling point that wou Post by: YELLOWFISH24 on Feb 24, 2015 moles of water=(180 calories*4.184 J/calories) / (40700J/mol)=0.0185mol
mass of water=0.0185mol*18g/mol=0.333g Title: Re: Calculate the amount of water (M.W. = 18.02 g/mol) at its boiling point that wou Post by: bio_man on Mar 1, 2015 Solved?
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