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Title: Calculate the ΔG° for a reaction with an equilibrium constant, K = 1,500, for Post by: xscapetomusic on Mar 23, 2015 Calculate the ΔG° for a reaction with an equilibrium constant, K = 1,500, for the following reaction: A + B ↔ AB
Title: Re: Calculate the ΔG° for a reaction with an equilibrium constant, K = 1,500, for Post by: habiba on Mar 23, 2015 8-) Have you learned about this formula? -- deltaG*' = -RTlnKeq
Similar Question What is the delta G (dG) for a reaction with an equilibrium constant of 10 at 25C ? R=8.3145 J/(mol*K) Give the answer in kJ Similar Question where R is the gas constant 8.314 J/(mol*k) T is in Kelvins so 25C +273= 298K Keq = 10 Use the formula above to obtain delta G. Note: there is a difference with obtaining free delta G vs delta G *" where *=knot "=prime. delta G = delta H- Tdelta S...but here use delta G*"= -RTlnKeq |