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Title: The balanced equation for the solubility equilibrium of Ba(OH)2 is shown below. What is the equilibr Post by: Whelan on May 6, 2015 The balanced equation for the solubility equilibrium of Ba(OH)2 is shown below. What is the equilibrium constant expression for the Ksp of Ba(OH)2?
Ba(OH)2(s) <-- --> Ba2+(aq) + 2 OH-(aq) A) Ksp = {[Ba2+][OH-]2}/{[Ba(OH)2][H2O]} B) Ksp = {[Ba2+][OH-]2}/[Ba(OH)2] C) Ksp = [Ba2+][OH-]2 D) Ksp = 1/{[Ba2+][OH-]2} Title: Re: The balanced equation for the solubility equilibrium of Ba(OH)2 is shown below. What is the equi Post by: hbutler2 on May 17, 2015 Content hidden
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