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Title: I am having trouble balancing equations in chemistry? Post by: smhchre on Jan 15, 2012 The problem reads:
Solid iron (III) sulfide reacts with gaseous hydrogen chloride to form solid iron (III) chloride and hydrogen sulfide gas. It says to balance the equation, but I have no idea where to begin. Could someone possibly walk me through this equation so that I have an example to work with for the others that I have to do? Title: I am having trouble balancing equations in chemistry? Post by: julieziemba on Jan 15, 2012 First write the formulas from the names given.
Iron (III) sulfide = Fe2S3 Hydrogen chloride = HCl Iron (III) chloride = FeCl3 Hydrogen sulfide = H2S Now write them in an equation that represents the written statement. Fe2S3 + HCl --> FeCl3 + H2S Then put coefficients in front of each compound so that the left side of the equation is equal to the right side. Fe2S3 + 6 HCl = 2 FeCl3 + 3 H2S (for coefficients of 1, don't put anything) Title: I am having trouble balancing equations in chemistry? Post by: julietalbot6 on Jan 16, 2012 First, insert all the chemical formulas into equation.
Fe2S3 (Iron sulfide) + HCl (Hydrogen Chloride) -> FeCl3 (Iron (III) chloride) + H2S (Hydrogen sulfide) Fe2S3 + HCl -> FeCl3+ H2S Next balance the equation. Ensure that there are equal amounts of everything on each side. Therefore, Fe2S3 + 6 HCl -> 2 FeCl3 + 3 H2S For compounds which are with the number 1 in front, ignore and do not write any number for the compound |