|
Title: What is the pH of a solution of a monoprotic acid with a pKa of 7 if it is 33.8 % ionized in solution? Give yo? Post by: rks23456 on Sep 4, 2012 What is the pH of a solution of a monoprotic acid with a pKa of 7 if it is 33.8 % ionized in solution? Give your answer to two decimal places.
Title: What is the pH of a solution of a monoprotic acid with a pKa of 7 if it is 33.8 % ionized in solution? Give yo? Post by: smlan3 on Sep 4, 2012 Use
pH = pKa + log([A-]/[HA]) A- is the acid's anion. If the solution is 33.8% ionized, that's how much is left in solution of the anion. HA is what is left of the acid in solution as unionized. pH = 7 + log[33.8/66.2] pH = 7 + (-0.2919) pH = 6.71 |