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Title: Peak current, phase angle, and peak voltage across capacitor of a circuit? Post by: Oasis on Sep 13, 2012 A series RLC circuit contains a 125.0 ? resistor, a 35.0 ?F capacitor and a 70.0 mH inductor. The circuit is attached to a 60 Hz oscillator with a peak voltage of 55.0 V.
a) What is the peak current? b) What is the phase angle? c) What is the peak voltage across the capacitor? Thanks for the help! Title: Peak current, phase angle, and peak voltage across capacitor of a circuit? Post by: lfiorill on Sep 13, 2012 Your main formulas here are V(inductor) = I(XL), V(capacitor) = I (XC), V(resistor) = I R, and V(generator) = I Z overall. That gives the magnitude. The phase angle comes from the diagram for
Z, with R along the x axis, XL along the positive y axis, XC along the negative y axis, so the net y component is XL-XC. The hypotenuse is Z, and the angle it makes with R is the phase angle. Good luck! |