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Science-Related Homework Help High School Level Science Topic started by: Rkamu on Sep 16, 2012



Title: A population of 4,000 butterflies at Hardy-Weinberg equilibrium contains 360 individuals with bent antennae?
Post by: Rkamu on Sep 16, 2012
A population of 4,000 butterflies at Hardy-Weinberg equilibrium contains 360 individuals with bent antennae - a recessive phenotype (genotype aa). What is the frequency of the crecessive allele (a) in the population after 6 generations?


Title: A population of 4,000 butterflies at Hardy-Weinberg equilibrium contains 360 individuals with bent antennae?
Post by: buidatsnpha on Sep 16, 2012
Um, technically you need a population of infinite size of randomly breeding individuals for HE equilibrium, but we'll overlook that for the moment... (usually 10,000 is the considered minimum effective size for HE -- otherwise you start running into genetic drift issues.)

The frequency of phenotypes of a simple dominant and recessive gene in a population are p squared + 2 pq + q squared... you can see that ratio when you do a simple heterozygous cross with a punnet square;
    | A   | a
---------------
A | AA | Aa
---------------
a | Aa  | aa

Note that the frequency of A and a in this population is 0.5 -- p=0.5 and q =0.5. If the frequency of A is 0.5, then the frequency of the AA genotype is 0.5 x 0.5 = 0.25 (or 1/4) (p squared) The frequency of the heterozygote is 2 x p x q = 2 x 0.5 x 0.5 = 0.5 (or 1/2).  The frequency of aa is q squared, or 0.5 x 0.5 = 0.25

Your problem involves a population... 4000 individuals, of which you know 360 are homozygous for bent antennae -- that number is your q squared value.

360/4000 = .09 = frequency of q squared = frequency of homozygous recessive in the population.

To find the frequency of the allele, you need to take the square root of q squared, which in this case is [sqrt 0.09] = 0.3 --  so 30% of the alleles in this population are the recessive allele, a.

Now, how are you going to figure out the frequency of the allele A in the population?  If 30% of the alleles are a, then 70% must be A, right?  (1 - 0.3 = 0.7)

Last part of the question: when there is no selection in a population at Hardy Weinberg equilibrium, what happens to the allele frequency?  Nothing!  After 6 generations, q still equals 0.3
(Or at least it would if the population had a larger effective size...)
More here: http://en.wikipedia.org/wiki/Hardy-weinberg_equilibrium and http://www.uwyo.edu/dbmcd/molmark/lect07/lect7.html