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Title: What is the magnitude of the resulting acceleration of the block? Post by: inquirytobio on Oct 21, 2012 The horizontal surface on which the block of mass 6.2 kg slides is frictionless. The force of 21 N acts on the block in a horizontal direction and the force of 42 N acts on the block at 60 degrees
What is the magnitude of the resulting acceleration of the block? The acceleration of gravity is 9.8 m/s^2 Answer in units of m/s^2 Title: What is the magnitude of the resulting acceleration of the block? Post by: Leobgood on Oct 21, 2012 The block slides horizontally without friction, so gravity is irrelevant.
The horizontal component of 42N at 60 deg is 42cos60 N = 21N If this force is in the same direction as the 21N force, the total accelerating force is f = 21N + 21N = 42N so accel is a = f/m = 42N/6.2kg = 6.77 m/s^2 If in the opposite direction, the net force is zero, and a = 0. There are other possibilities too. |