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Title: Can someone explain how the sodium-potassium pump returns the membrane to its resting potential? Post by: smluke2000 on Dec 11, 2012 From what I understand, after repolarization, the potential reaches below its resting potential, and the membrane wants to return to that resting potential, -70mV. To do this, the sodium-potassium pump ejects 3 Na ions and receives 2 K ions repeatedly. Since they're both positive ions, it seems to me that the inside of the membrane should become more negative, since during each transfer the net loss is one positive ion.
What am I missing? Title: Can someone explain how the sodium-potassium pump returns the membrane to its resting potential? Post by: Leona Ariane on Dec 11, 2012 Content hidden
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