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Title: If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability ... Post by: boojis on Jan 9, 2013 If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability that child will have blood type A Rh-?
Title: If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability ... Post by: willajereca on Jan 9, 2013 A mother who is blood type AB could pass either an A or a B allele to her son or daughter.
A father who is blood type O can only pass an O allele to his son or daughter. This couple could have children of either blood type A (O from father and A from mother) or blood type B (O from father and B from mother). The child, therefore, will have equal chances of being either A or B blood type. Title: If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability ... Post by: boojis on Jan 9, 2013 thats not answer to that question. Its a number.
Title: If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability ... Post by: bio_man on Jan 9, 2013 Wouldn't it then be 50%, or 1:2 ?
Title: If a women with the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability ... Post by: tverhesen on May 3, 2013 The question is asking two things.
1. What's the probability of the child having a RH- 2. What's the probability of the child having A blood type The Answer is 1/4 = 0.25 This is a question that a punnet square is optimal. 1. RH- = dd RH+ = Dd or DD (because they do not specify if it is homozygous Dominant you take the Dd) D d d Dd dd = 1/2 RH- 1/2 RH+ d Dd dd 2. ii = O IAIB = AB IA IB ii IAii IBii = 1/2 A 1/2 B ii IAii IBii 1/2 (RH-) x 1/2 (A) = .25 |