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Title: what is the equation of an upside down parabola in the first quadrant? Post by: Hurley on Jan 29, 2013 i have a question where the parabola's in the positive x and y quadrant and its facing down. is there an equation for something like this?
thanks in advance Title: what is the equation of an upside down parabola in the first quadrant? Post by: Leobgood on Jan 29, 2013 Sure! y=-(x-20)^2+20 will do it. The - on the x^2 makes it flip upside down. The -20 in the parenthesis makes it move 20 to the right. The +20 outside the parenthesis makes it move 20 up.
jr Title: what is the equation of an upside down parabola in the first quadrant? Post by: smooch1020 on Jan 29, 2013 Try -(x-5)^2+16
The (x-5) moves it to the right on the x axis. The +16 moves it up 16 units on the y axis. Title: what is the equation of an upside down parabola in the first quadrant? Post by: hurley982 on Jan 29, 2013 The parabola opens downward, so 'a' will be negative.
The vertex is in QI, so h and k will both be positive. Equation: y = a(x - h)² + k, where a < 0, h and k > 0 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ |