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Title: electrochemistry Nernst Equation Post by: nevada on May 11, 2013 The overall reaction in the lead storage battery is
Pb(s) + PbO2(s) + 2H+(aq)+2HSO-4 (aq) ---->2PbSO4(s)+2H2O)(l) Calculate E at 25C for this battery when [H2SO4] = 4.5 M, that is, [H+] =(HSO-4)= 4.5 M. At 25C, E° = 2.04 V for the lead 4 storage battery. i do know know how to do this question, all i know is that i have to use the Nernst Equation I think the first thing that i have to do is split the equation into 2 half reaction. But i do not know how to do it for this question, there is 4 reactant and only 2 product i am thinking i should split it up like this Pb(s) + PbO2(s) ---->2PbSO4(s) and 2H+(aq)+2HSO-4 (aq)---->2H2O)(l) am i going right? Title: Re: electrochemistry Nernst Equation Post by: Laser_3 on May 12, 2013 Content hidden
Title: Re: electrochemistry Nernst Equation Post by: duddy on May 12, 2013 @nevada, please mark as solved once you have a chance.
Title: Re: electrochemistry Nernst Equation Post by: Half reaction on May 12, 2013 What napped to the 2H+(aq) and 2H2O)(l. In the half reaction?
Title: Re: electrochemistry Nernst Equation Post by: Laser_3 on May 12, 2013 Hi,
Well, I stated that the equation is not balanced. You can go ahead and balance with the Oxygen with H2O and hydrogen with H+. And at the end, you can substitute H+ as H2SO4 (which dissociate and become H+ and HSO4-). Since the equation given is already balanced, I didn't not realized there is a need to go through the balancing process. Best, Laser |