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Title: What is the probability (see details in question) of getting a pea with genotype RRYY? Post by: jtoya18 on Jun 22, 2013 In a dihybrid cross that follows the pattern of inheritance of two traits (yellow/green (Yy), and round/wrinkled (Rr) peas the F1 generation with genotype RrYy were self-cross. What is the probability of getting a pea with the genotype RRYY?
I don't care if answer is percentage or fraction... Title: What is the probability (see details in question) of getting a pea with genotype RRYY? Post by: $amanthaP24 on Jun 22, 2013 25%
Title: What is the probability (see details in question) of getting a pea with genotype RRYY? Post by: $abood$ on Jun 22, 2013 25%
1/4 one in four I think XD Title: What is the probability (see details in question) of getting a pea with genotype RRYY? Post by: RiseofEvil on Jun 22, 2013 1/16.
You could either do the 4x4 Punnett square, RrYy x RrYy, or you could do the 2 genes separately: The chance of getting RR from Rr x Rr is 1/4: ____R____r___ R__RR___Rr__ r___Rr___rr___ The same is true of getting YY from Yy x Yy. And 1/4 x 1/4 is 1/16. |