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Title: Precalculus summer homework help...? Post by: smokebomb13 on Sep 9, 2013 Your Open QuestionShow me another »
Precalculus summer homework help...? i need some help with these problems. can you please tell me how to do these thanks. 1. the lines L1 and L2 are perpendicular and given by L1: 4ax+2by=1 L2: 3ax-by=5 find 12(a^2)+4b^2 2.for real numbers m and n, let m(+)n=2mn-n^3. find 4(+)2. (the + sign is inside a circle) 3.for what values of k does the equation (x^2)-kx+1=0 have imaginary roots? 4.let f(x)=x^3-ax^2+bx-c. if f(0)=1 and f(1)=4. find b-a 5.which of the following functions are one-to-one? a) y=lxl b)y=4x-3 c)y=(3x+4)/ (x-2) 6.find the equation of the perpendicular bisector of the segment joining P(-2,-4) and Q(8,-8) 7. write a polynomial equation that has the following three roots: 5, (5i(? 3)-5)/2, and (-5i? 3-5)/2 i really want to know HOW to do these. thanks Title: Precalculus summer homework help...? Post by: iluvtalking on Sep 9, 2013 Content hidden
Title: Precalculus summer homework help...? Post by: datguy on Sep 9, 2013 2by = -4ax + 1
y = (-2a/b)x + 1/(2b) by = 3ax - 5 y = (3a/b)x + 5/b -2a/b = -b/(3a) -6a^2 = -b^2 6a^2 = b^2 ?(6)a = b 12a^2 + 24a^2 36a^2 No idea what a equals. ---------------- 2(4)(2) - (2)^3 16 - 8 8 ---------------- x^2 - kx + 1 = 0 k ? 2 ------------------ c = -1 -a + b = 3 --------------- a) no b) yes c) i think so ------------------ (x - 5)(2x + 5)^2 = (5i?(3))(-5i?(3)) (x - 5)(2x + 5)^2 = 25*3 (x - 5)(2x + 5)^2 = 75 (x - 5)(4x^2 + 20x + 25) = 75 4x^3 - 20x^2 + 20x^2 - 100x + 25x - 125 = 75 4x^3 - 75x - 200 = 0 |