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Title: Equilibrium Partial Pressures Question Post by: biostudent123 on Feb 20, 2014 At 1000 K, Kp = 19.9 for the reaction Fe2O3(s)+3CO(g)⇌2Fe(s)+3CO2(g)
A) What are the equilibrium partial pressures of CO and CO2 if CO is the only gas present initially, at a partial pressure of 0.912atm ? Pe CO, Pe CO2 = ? Title: Re: Equilibrium Partial Pressures Question Post by: padre on Feb 21, 2014 Content hidden
Title: Re: Equilibrium Partial Pressures Question Post by: biostudent123 on Feb 22, 2014 How did you get 0.952moles ? i tried following the sample, but i get far off values
(3x/3) x0.938^3 / (3-3x/3) x 0.938^3 = 3x/(3-3x) x=0.952moles Title: Re: Equilibrium Partial Pressures Question Post by: padre on Feb 23, 2014 19.9 = 3x/(3-3x)
19.9(3-3x) = 3x distribute 59.7 - 59.7x = 3x 59.7 = 3x + 59.7x simplify 59.7 = 62.7x 59.7 / 62.7 = x 0.952 Title: Re: Equilibrium Partial Pressures Question Post by: biostudent123 on Mar 5, 2014 Thank you padre, at first i didnt understand it in this format, i saw the exact same thing but on a PDF file, which made me visualize the concepts better.
Title: Re: Equilibrium Partial Pressures Question Post by: padre on Mar 5, 2014 NP Glad to help
Title: Re: Equilibrium Partial Pressures Question Post by: mae m on Sep 12, 2020 !!!
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