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Title: A single-turn plane loop of wire with a cross-sectional area 200 cm2 Post by: poonbaby on Apr 19, 2014 A single-turn plane loop of wire with a cross-sectional area 200 cm2 is perpendicular to a magnetic field that increases uniformly from 0.200 T to 2.800 T in 2.20 seconds. What is the magnitude of the induced current if the resistance of the coil is 8.00 Ω?
Title: Re: A single-turn plane loop of wire with a cross-sectional area 200 cm2 Post by: duddy on Apr 19, 2014 Hi,
Induced current I = e/R = (dB/dt)A/R = [(2.8T -0.2T)/(2.2s)](200*10-4m2)/(8Ω) = 2.95mA Hope this help you. |