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Title: Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that Post by: fosmanali01 on Jun 5, 2014 .Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that is co-terminal to θ and is not equal to θ.
Title: Re: Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that Post by: sravancv on Jun 18, 2014 so here as sin\({\theta}\) is = 0.6293
\({\theta}\) = arc sin (0.6293) = 38.9984 but as we need it to be in second quadrant it is 90+38.9984 = 128.9984 degrees Title: Re: Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that Post by: bio_man on Jun 18, 2014 but as we need it to be in second quadrant it is 90+38.9984 = 128.9984 degrees Why does it need to be in the second quadrant? Title: Re: Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that Post by: sravancv on Jun 18, 2014 Its becoz theta is said to be in between 90 and 180 degrees which indirectly says that it should be in Q2
Title: Re: Given sinθ=0.6293 where 900≤θ≤1800, determine the smallest positive angle that Post by: bio_man on Jun 18, 2014 where 900≤θ≤1800 Okay, but then how do you rationalize this, what does this mean? |