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Title: Aball with a horizontal speed of 1.3m/s rolls off a bench 3.7m high. Post by: kme8124 on Sep 17, 2014 A ball with a horizontal speed of 1.3m/s rolls off a bench 3.7m high.
How long will the ball take to reach the floor? How far from a point on the floor directly below the edge of the bench will the ball land? Title: Re: Aball with a horizontal speed of 1.3m/s rolls off a bench 3.7m high. Post by: Krnfx on Sep 17, 2014 To get the time for the ball to reach the floor it's (3.7m)/(9.8m/s) <-[the constant for standard acceleration due to gravity]. That'd give you 0.38s rounded off, then multiply that 0.38 seconds by the 1.3m/s to cancel the unit seconds and you'd get 0.49m. Overall the equation(s) would look like (3.7m)/(9.8m/s) = 0.38s | (0.38s)(1.3m/s) = 0.49m/
Interpretation: The ball would take 0.38 seconds to reach the floor, and it would land 0.49m away from a point below the edge of the bench |