Title: What is the probability of obtaining a blue parakeet when two green heterozygous parakeets... Post by: peaches+cream on Oct 29, 2014 Question one:
Feather colour in pararkeets is controlled by two genes. For one pigment gene, the B allel produces blue colour and the b allele does not produce any colour. For the other pigment gene, the Y allel produces yellow colour and the y allele does not produce any colour. Any genotype containing at least one B allele and one Y allele will produce a green parakeet. Which of the following parental genotypes could produce offspring with the four colour patterns? A. bbYY x bbyy B. BbYY x Bbyy C. BBYy x BbYy D. Bbyy x bbYy HINT: Use a punnett square to demonstrate your answer is correct. Do you need punnett squares of size 4 rows X 4 columns? (I'm thinking that the answer is B, but I don't know if I did the work right). Question two: (Almost like the last question) But now it asks: What is the probability of obtaining a blue parakeet when two green heterozygous parakeets are crossed? A. 0 B. 9/16 C. 3/16 D. 1/4 If anyone could help me understand it would be much appriciated!!! :) Title: What is the probability of obtaining a blue parakeet when two green heterozygous parakeets... Post by: bio_man on Oct 29, 2014 Hope the attachment helps...
Title: What is the probability of obtaining a blue parakeet when two green heterozygous parakeets... Post by: peaches+cream on Oct 30, 2014 Thank you!! But im also hoping for an explination too so when I go into the exam and come across a question like this one ill know how to do it :P
Title: What is the probability of obtaining a blue parakeet when two green heterozygous parakeets... Post by: bio_man on Oct 30, 2014 Hey peaches+cream, it's easy to do, but just very time consuming, because you will have to create four dihybrid crosses, like:
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