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Science-Related Homework Help Chemistry Topic started by: OldSpice on Dec 8, 2014



Title: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: OldSpice on Dec 8, 2014
The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is the percentage of carbon in the compound?
A) 3.959%
B) 4.618%
C) 6.991%
D) 21.09%
E) 67.30%


Title: Re: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: Electric on Dec 12, 2014
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Title: Re: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: OldSpice on Dec 14, 2014
Perfect!

..Thank you so much for your support


Title: Re: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: Electric on Dec 14, 2014
My pleasure


Title: Re: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: loeinjhonson on May 19, 2022
The formula for the illegal drug cocaine is C17H21NO4. What is the mass percentage of oxygen in the compound?


Title: Re: The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is th
Post by: bio_man on May 19, 2022
The formula for the illegal drug cocaine is C17H21NO4. What is the mass percentage of oxygen in the compound?